how to remember that a inductor and capacitor is replaced by short circuit or open circuit in the transient and steady state??
Most of the students usually being confused that inductor is replaced by short or open circuit in the transient or steady state... in the time of exam...
So here is the solution:
The transient state occurs at t=0 and steady state occurs at t=∞.
So, S=∞ at the transient state and s=0 at the steady state.
(where s=frequency; frequency=1/time;)
Now we know that the laplace transform of L and C are
(Ls) and (1/Cs).
So put the value of s in the Ls and 1/Cs.
when S=∞(i.e, in the transient state)
(Ls)Ω→∞Ω→open circuit.
(1/Cs)Ω→0Ω→short circuit.
when S=0(i.e, in the steady state)
(Ls)Ω→0Ω→Short circuit.
(1/Cs)Ω→∞Ω→open circuit.
So here is the solution:
The transient state occurs at t=0 and steady state occurs at t=∞.
So, S=∞ at the transient state and s=0 at the steady state.
(where s=frequency; frequency=1/time;)
Now we know that the laplace transform of L and C are
(Ls) and (1/Cs).
So put the value of s in the Ls and 1/Cs.
when S=∞(i.e, in the transient state)
(Ls)Ω→∞Ω→open circuit.
(1/Cs)Ω→0Ω→short circuit.
when S=0(i.e, in the steady state)
(Ls)Ω→0Ω→Short circuit.
(1/Cs)Ω→∞Ω→open circuit.
Post a Comment